python执行另一个脚本

In this post you will find a function I wrote solving a problem of randomization with constrains in Python. For a psychological experiment () I am planning to conduct I needed a list of stimuli names quasi-randomized.  Fifty percent of the items in the list be followed by a stimulus in the same colour and the remaining 50 % would be followed by a stimulus in a different colour.

在本文中，您将找到我编写的函数，用于解决Python中带有约束的随机化问题。 对于心理实验（ ），我计划进行操作，我需要一个准随机命名的刺激物名称列表。 列表中百分之五十的项目后面是相同颜色的刺激，其余的50％之后是不同颜色的刺激。

Python脚本 (Python script)

from random import shufflefrom collections import Counterliststim = []colors, firstfigures = ['Black', 'Blue'], ['Rect', 'Triangle', 'X', 'Circle']secondfigures = firstfiguresfor col in colors:    for figure in firstfigures:        for figure2 in secondfigures:            liststim.append(col + '-' + figure + '_' + figure2)def randShift(listostim, ntrials):    '''    Will randomize 50 % of shifting trials    based on that each filename (of the images) starts with Black or Blue-.        listostim is a list of trials    ntrials is an integer indicating number of trials    '''    nEachstim = ntrials/len(liststim) #Number of each stim is going to be even    stimList = listostim     trialTypes = []     stims = []    countOfStim = dict((el,0) for el in stimList)    count = {'ns':0,'s':0}    for i in range(ntrials):        shuffle(stimList)        for idx in range(len(stimList)):            if not stims:                countOfStim[stimList[idx]] +=1                stims.append(stimList[idx])                count['ns'] +=1                trialTypes.append("No-Shifting")            elif stims:                if count['s'] <= ntrials/2:                    if countOfStim[stimList[idx]] <= nEachstim-1: if stimList[idx][:5] != stims[i-1][:5]: count['s'] +=1 countOfStim[stimList[idx]] +=1 stims.append(stimList[idx]) trialTypes.append("Shifting") else: count['ns'] +=1 countOfStim[stimList[idx]] +=1 stims.append(stimList[idx]) trialTypes.append("No-Shifting") elif count['s'] > ntrials/2:                    if countOfStim[stimList[idx]] <= nEachstim-1:                         if stimList[idx][:5] == stims[i-1][:5]:                            count['ns'] +=1                            countOfStim[stimList[idx]] +=1                            stims.append(stimList[idx])                            trialTypes.append("No-Shifting")    #Frequency of the trialtypes    freq = Counter(trialTypes).values()from random import shufflefrom collections import Counterliststim = []colors, firstfigures = ['Black', 'Blue'], ['Rect', 'Triangle', 'X', 'Circle']secondfigures = firstfiguresfor col in colors:    for figure in firstfigures:        for figure2 in secondfigures:            liststim.append(col + '-' + figure + '_' + figure2)def randShift(listostim, ntrials):    '''    Will randomize 50 % of shifting trials    based on that each filename (of the images) starts with Black or Blue-.        listostim is a list of trials    ntrials is an integer indicating number of trials    '''    nEachstim = ntrials/len(liststim) #Number of each stim is going to be even    stimList = listostim     trialTypes = []     stims = []    countOfStim = dict((el,0) for el in stimList)    count = {'ns':0,'s':0}    for i in range(ntrials):        shuffle(stimList)        for idx in range(len(stimList)):            if not stims:                countOfStim[stimList[idx]] +=1                stims.append(stimList[idx])                count['ns'] +=1                trialTypes.append("No-Shifting")            elif stims:                if count['s'] <= ntrials/2:                    if countOfStim[stimList[idx]] <= nEachstim-1: if stimList[idx][:5] != stims[i-1][:5]: count['s'] +=1 countOfStim[stimList[idx]] +=1 stims.append(stimList[idx]) trialTypes.append("Shifting") else: count['ns'] +=1 countOfStim[stimList[idx]] +=1 stims.append(stimList[idx]) trialTypes.append("No-Shifting") elif count['s'] > ntrials/2:                    if countOfStim[stimList[idx]] <= nEachstim-1:                         if stimList[idx][:5] == stims[i-1][:5]:                            count['ns'] +=1                            countOfStim[stimList[idx]] +=1                            stims.append(stimList[idx])                            trialTypes.append("No-Shifting")    #Frequency of the trialtypes    freq = Counter(trialTypes).values()

The last part is the crucial part since the above code will not produce the required list 100 % of the time. The script, therefore, first checks that the above script has generated the output needed. That is, it is 50% items that are of a color and then followed by a different color? An additional check is also made to make sure that there are so many items that were  required (i.e-, number of trials; ntrials). Last code will call the function again until the requirements are fulfilled.

最后一部分是关键部分，因为上面的代码不会在100％的时间内生成所需的列表。 因此，该脚本首先检查上述脚本是否已生成所需的输出。 也就是说，是50％的商品是一种颜色，然后是另一种颜色？ 还进行了另一项检查，以确保所需的项目太多（即，试验次数；试验）。 最后的代码将再次调用该函数，直到满足要求为止。

The script is solving my problem and it works pretty quick. However, if there is a more elegant method I would love to see it.

该脚本正在解决我的问题，并且运行很快。 但是，如果有更优雅的方法，我很乐意看到。

翻译自:

python执行另一个脚本